Question

Consider the numbers 4^n whose n is a natural number chek whether there a any value n for which 4^n ends with the digit​

Answer 1

Step-by-step explanation:

This means that the prime factorisation of 4n should contain the prime number 5. ... Since 5 is not present in the prime factorization, so there is no natural number n for which 4n ends with the digit zero.

Answer 2

$✅❤️Answer❤️$

For the number 4^n to end with digit zero for any natural number n, it should be divisible by 5. This means that the prime factorisation of 4^n should contain the prime number 5.But it is not possible because 4^n =(2)²^n

so 2 is the only prime in the factorisation of 4^n. Since 5 is not present in the prime factorization, so there is no natural number n for which 4^n ends with the digit zero.