Question

Consider the numbers 4", where n is a natural number. Check whether
there is any value of n for which 4" ends with the digit zero.
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Answer 1

let us take a example of a number which ends with a digit 0

so,

10 = 2*5

100 = 2*2*5*5

Here we note that number which is ending with 0 has both 2 &5 as their prime factor

whereas 4^n ( 2*2)^n

Does not have 5 as prime factor

so, it does not end with 0

Therefor, 4^n cannot end with 0 of any natural number (n)