Question

Consider the numbers between 100&300 which leave remainder 2 on division by 3

Answer 1

Answer:

Numbers between 100 and 300 which leave remainder 2 on division by 3 are101 104 107 110 .........299a First number of this sequence = 101b Last number of this sequence = 299d Sum of all numbers in the sequence = n/2a+an∴ Sum of all numbers = 13400

Step-by-step explanation:

Answer 2

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