consider the numbers from 100 to 400 that leaves a reminder 1 on division by 7
a. write the sequence of such numbers?
b.how many numbers are there?
c.find the sum of such numbers
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Step-by-step explanation:
Clearly, the numbers will be multiples of 7 with an extra "1" .
a. 8,15, 22, 29, ... 400
b. 400 = a + (n-1)d
392 = (n-1)7
392 = 7n - 7
399 = 7n
n = 57
c. Sn = (57/2)[2a + (n-1)7]
= (57/2)[16 + (56)*7]
= (57/2)(408)
= 57*204
= 11628
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