Physics, asked by mohitydv2506, 5 days ago

Consider the plane makes intercepts of 28, 38, 4 Å on the coordinate axis of the crystal with a:b:c =4:3:2. The crystal is orthorhombic crystal. Calculate the miller indices of the given plane of the crystal. (A) (4,1,1) (B) (4,3,2) (C) (4,2,1) (D) (4,4,4) ​

Answers

Answered by ankan2778
0

Answer:

Rules for Miller Indices:

1. Determine the intercepts of the face along the crystallographic axes, in terms of unit cell dimensions.

2. Take the reciprocals of the coefficients of the intercept

3. Clear fractions

4. Reduce to the lowest integer

Taking reciprocal of the coefficient-

We get-

2

1

,

2

1

,

3

1

Reduce to lowest integer-

Multiply with 6 ⇒

2

1

×6,

2

1

×6,

3

1

×6⇒3,3,2

Hence, the miller indices for the given plane is 332

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