Question

consider the polynomial p(x)=x3-4x2+ax-3 A.find a if, when p(x) is devided by x+1, the the remainder is -12
B.find all the factors of p(x)
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Answer 1

Answer:

ok

Step-by-step explanation:

a(x) ^3 +4(x)^2+3x-4 Now x=3 , put the value of x which is 3 f(3) = a(3) ^3 +4(3) ^2+3(3) -4... (i) 27a+36+9-4 27a+41=0....(ii) (x) ^3-4(x)+a 3^3-4(3) +a 27-12+a 15+a=0....(iii) As the remainder is same , we equate the eqs(ii) &(iii) 27a+41=15+a 26a=-26 a=-1 -1 is the answer... If iam not worng... Hope the answer help you...