Question

Consider the polynomial pu) - 5x^3 - 2x^2 + 3x - 2.
If we replace x by -1 everywhere in p(x), we get
P(1) - 5*(1)'- 2* (1) + 3 * (1
-5-2+ 3-2
4
So, we say that the value of px.x) at r= 1 is 4.
p(0) - S(0)' -- 2(0)+ 3(0) -2
Similarly
.-2
Can you find p-1)?
​

Answer 1

Step-by-step explanation:

5×-1-2×-2+3×-2

-5 +4 +6

-1 +6

5ans