Question

Consider the rational function p=(5,125,000V2−449,000V+19307)/(125V2(1,000V−43)), what value of p is the horizontal asymptote of the function?

Answer 1

Answer:

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Answer 2

Given:

Given rational function, $p=\frac{5,125,000V^2-449,000V+19307}{125V^2(1000V-43)}$

Also, the given rational function contains a horizontal asymptote.

To find:

We should to find the value of $p$.

Solution:

Before solving the question, simplify the terms in the denominator.

$\Rightarrow p=\frac{5,125,000V^2-449,000V+19307}{125V^2(1000V-43)}$

$\Rightarrow p=\frac{5,125,000V^2-449,000V+19307}{125000V^3-5375}$

According to the question, the given function has a horizontal asymptote.

If we observe the given function carefully,

The highest degree in the numerator is equal to 2 and the highest degree in the denominator is 3.

Here, the degree of the numerator (2) is less than the denominator (3).

So, the horizontal asymptote is $y=0.$

But here, the value of $p=y$.

So, the value of $p=0$.

Therefore, the value of $p$ is equal to zero (0).