Question

Consider the reaction at 300 K C6 H6 + 15/2O2 -> 60 2 + 3 H2 O2 dh=-3 2 7 1 kj what is Delta u for the combustion of 1.5 mole of benzene at 27 degree Celsius

Answer 1

Answer:

mark me as brainliest and follow me

Answer 2

Answer:

Delta u for the combustion of 1.5 moles of benzene at 27 degrees Celsius is $-49065.5KJ$

Explanation:

$\mathrm{C}_{6} \mathrm{H}_{6}+\frac{15}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow 6 \mathrm{CO}_{2(\mathrm{~g})}+3 \mathrm{H}_{2} \mathrm{O}, \Delta \mathrm{H}=-3271 \mathrm{~kJ}$

For this reaction $\Delta \mathrm{U}=\Delta \mathrm{H}$ at constant pressure $\&\ volume.$

$\Delta \mathrm{U}=\Delta \mathrm{H}$

For  mole benzene

$\begin{aligned}\Delta U &=1.5 \times \Delta \mathrm{H} \\&=1.5 \times-3271 \mathrm{~kJ} \\&=-4906.5 \mathrm{~kJ} .\end{aligned}$