Question

consider the reaction ch4 + 2 O2 gives CO2 + 2 H2O:- 1)calculate the volume of oxygen required to produce 40 grams of carbon dioxide.2) calculate the amount of carbon dioxide formed from 2 moles of Methane. 3) calculate the amount of Methane reacting with 25 liters of oxygen. 3) calculate number of molecules of oxygen required to produce 50 litres of water.​

Answer 1

Answer:

The reaction is CH4+2O2→CO2+2H2O.

At room temperature, water will condense to form liquid water.

1 mole of methane reacts with 2 moles of oxygen to form 1 mole of oxygen.

10 ml (0.445 moles) of methane will react with 20 ml (0.89 moles) of oxygen to form 10 ml (0.445 moles) of carbon dioxide.

Hence, the resulting mixture will contain 10 ml of unreacted methane and 10 ml of carbon dioxide.

The total volume of the mixture will be 20 ml.

Explanation:

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Answer 2

Given:

Chemical Reaction ⇒ CH4 + 2 O2 → CO2 + 2 H2O

To Find:

1) volume of O2 required to produce 40 gm CO2.

2) amount of CO2 formed from 2 moles of CH4.

3) amount of CH4 reacting with 25 liters of O2.

4) number of molecules of O2 required to produce 50 litres of H2O.​

Calculation:

According to the given reaction:

1) 44 gm CO2 requires O2 = 64 gm

⇒ 40 gm CO2 requires O2 = (64/44) × 40 = 58.18 gm.

2) Amount of CO2 produced by 1 mole CH4 = 44 gm

⇒ Amount of CO2 produced by 2 moles CH4 = 88 gm.

3) Amount of CH4 reacting with 2 liters of O2 = 16 gm

⇒ Amount of CH4 reacting with 25 liters of O2 = 16 × 25 = 400 gm.

4) No of moles of O2 required to produce 2 litres of H2O = 2

⇒ No of moles of O2 required to produce 50 litres of H2O = 50 moles.