Question

consider the reaction ch4 + 2 O2 gives CO2 + 2 H2O:- 1)calculate the volume of oxygen required to produce 40 grams of carbon dioxide.2) calculate the amount of carbon dioxide formed from 2 moles of Methane. 3) calculate the amount of Methane reacting with 25 liters of oxygen. 4) calculate number of molecules of oxygen required to produce 50 litres of water. 5)calculate the volume of ch4 reacting with 20g of of oxygen.​

Answer 1

Answer:

it is a nice question from redox titration

let me try my best

Explanation:

ch4+2o2=co2+2h2o

here only ch4 and co2 are part of change in oxidation number

if you want to apply law of equivalent you can apply for ch4 and co2

2 moles of o2 used = 1 mole co2 formed

so  calculate mole for volume

convert 40 gm co2 into moles

moles = weight / molecular mass

=40/44=0.9mole

2 moles of o2 used = 1 mole co2 formed

x moles of o2 used = 0.9 mole co2 formed

by criss cross

x=1.8

moles of o2 = 1.8

1 mole of o2 = 22.4 lt

1.8 mole of o2 = x

by criss cross

x=1.8*22.4 lt

v=40.32 lt

2)for second one you can apply law of equivalent

law of equivalent = moles * valency factor

by law of equivalent

equivalent of ch4=equivalent of co2

2*8=x*8

x=2

moles of co2=2

3)1 mole of ch4 reacts with 2*22.4 lt o2

x moles of ch4 reacts with 25 lt o2

x=25/44.8

x=0.55

moles of ch4 = 0.55

moles = weight / molecular weight

moles * molecular weight  = weight

0.55*16=weight

8.8 gm =  weight

therefore 8.8 gm reacts with 25 lt oxygen

4)by law of moles

2 moles of oxygen used = 2 moles of h2o formed

or it can be written as

2 moles of oxygen reacts and forms 44.8 lt h2o

x moles of oxygen reacts and forms 50 lt h2o

x=2.23

hence 2.23 moles of oxygen reacts and forms 50 lt oxygen

1 mole oxygen has 6.023*10^23 molecules

2.23 moles of oxygen has x molecules

by criss cross

2.23 moles  has 13.43*10^23 molecules

that means 13.43 * 10^23 molecules of o2 produce  lt oxygen

5)1 mole of ch4 used = 2 moles of o2 used

1  moles of ch4 used =64 gm o2 used

x moles of ch4 used = 20 gm o2 used

by criss cross

x=0.31

1 mole o2 has 22.4 lt

0.31 mole o2 has x lt

by criss cross

x=6.94  lt

volume of ch4 reacting with 20 gm oxygen  = 6.94 lt