Question

Consider the reaction : N₂ (g) + 3H₂ (g) → 2 NH₃ (g)
The equality relationship between d[NH₃]/dt and - d[H₂]/dt is
(a) + d[NH₃]/dt = - 2/3 d[H₂]/dt
(b) + d[NH₃]/dt = - 3/2 d[H₂]/dt
(c) d[NH₃]/dt = - d[H₂]/dt
(d) d[NH₃]/dt = - 1/3 d[H₂]/dt

Answer 1

Explanation:

Consider the reaction : N₂ (g) + 3H₂ (g) → 2 NH₃ (g)

The equality relationship between d[NH₃]/dt and - d[H₂]/dt is

(a) + d[NH₃]/dt = - 2/3 d[H₂]/dt

(b) + d[NH₃]/dt = - 3/2 d[H₂]/dt

(c) d[NH₃]/dt = - d[H₂]/dt

(d) d[NH₃]/dt = - 1/3 d[H₂]/dt

Answer 2

Answer:

(c) is correct one of those options...

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