Question

Consider the reaction:
NO2(g)+CO(g)→NO(g)+CO2(g) (1)
which occurs in two elementary steps:
NO2+NO2→NO+NO3 (slow) (2)
NO3+CO→NO2+CO2 (fast) (3)
Derive the rate law.

Answer 1

Answer:

Reaction of CO(g) with NO2(g)

CO(g) + NO2(g) ? NO(g) + CO2(g)

At low temperatures, the experimentally determined rate law expression is:

Rate = k [NO2]2

A two step reaction mechanism is suggested

Step 1 SLOW NO2(g) + NO2(g) ? NO3(g) + NO(g)

Step 2 FAST CO(g) + NO3(g) ? CO2(g) + NO2(g)

CO(g) + NO2(g) ? NO(g) + CO2(g)