Question

Consider the reaction of KMnO4 with H2O2 :

2KMnO4 + 5H2O2 + 4H2SO4 2KHSO4 +

2MnSO4 + 5O2 + 8H2O

20 mL of the H2O2 solution is completely reacted

with 50 mL of 0.12 M KMnO4 solution as per

above reaction. The % W/V of H2O2 solution is​

Answer 1

Answer:

2KMnO

4

(aq)+5H

2

O

2

(aq)+3H

2

SO

4

(aq)→K

2

SO

4

(aq)+2MnSO

4

(aq)+5O

2

(g)+8H

2

O(aq)

This is the balance chemical equation taking place :

This reaction suggests that for the for the same molarity ,suppose 0.12M , if KMnO4 has 20mL , then H2O2 volume which will react completely is 5/2∗20=50mL .

As given is only 20 mL H

2

O

2

so 0.12M (50mL ) = actual molarity * 20 mL

actual molarty = 0.12∗50/20=0.30M.

As 1 M H

now you can find the ans...