Question

Consider the reactions and the respective enthalpies of reaction.
NH3(g) + 3C12(g) = NCI3(g) + 3HCl(9), AH = X
N2(g) + 3H2(g) = 2NH3(g), AH = y
H2(g) + Cl2(g) = 2HCl(9), AH = Z
Then using this information, the enthalpy of formation of NC13 is
2x - y + 3z
Y_32
2 2
у 3z
-x+ž
-x+
22
*-*-*
Y 3z
2 2​

Answer 1

Answer:

enthalpy for the formation of NCI3 is

x + y/2 -3/2 z