Question

consider the real valued fun
F(x)= x-3/x^2-x-6

Find the domain of f(x).​

Answer 1

Step-by-step explanation:

$f(x) = \frac{x - 3}{ {x}^{2} - x - 6} = \frac{(x - 3)}{( {x}^{2} - 3x + 2x - 6)} = >$

$f(x) = \frac{(x - 3)}{x(x - 3) + 2(x - 3)} = \frac{(x - 3)}{(x + 2)(x - 3)}$

So f(x) doesn't exist at x=3 and x=2 So the domain of f(x) => [-infinity , infinity] -{3,-2}. Hope it helps you.

Answer 2

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check the attachment