Consider the redox reaction :
K2Cr2O7 + HCI – CrCl3 + Cl2 + KCl + H2O
Which of the following is/are correct?
For 1 mol of K2Cr207. 14 mole HCl is required
Equivalent wt. of HCl is 85.166
For 1 mole of K2Cr207, only 6 mole of HCI act as reducing agent
Equivalent wt of HCI is 36.5
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Answer, 1 and 4 is correct .... ❤️ ❤️ ❤️
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