Question

Consider the sequence. 7, 13, 19....
a)Find its 10th term
b)Write its algebraic expression​

Answer 1

Answer:

10th term = 61

Step-by-step explanation:

First term, a= 7,

common difference, d= 13-7= 6

n = 10

$a_{10} = a + (n - 1)d \\ a_{10} = 7 + (10 - 1) \times 6 \\ = 7 + 9 \times 6 \\ = 7 + 54 \\ = 61 \\ \\ \\ hope \: it \: helps \: u$

Answer 2

Step-by-step explanation:

a1o= a +(10-1)×6

= 7+9×6

= 61

where a= 7

and d= 6