Question

Consider the sequence of multiples of 7 between 200 an
a) Find the first term and the last term?
b) How many terms are there in
this sequence?
3) Find the sum of the terms in this sequence​

Answer 1

Step-by-step explanation:

a=7

an=196

a. so the First term is 7 and last term between 200 is 198.

b. An=a+(n-1) d

196=7+(n-1)7

196-7=(n-1)7

189/7=n-1

27+1=n

28=n

hence total number of terms is 28

c..sum=28/2(7+196)

sum=14*203

sum=2842