Question

Consider the set A = {3,4,5} and the number of null relations , identity relation , universal relations reflexive relations on A are respectively n1,n2,n3 and n4 then the value of n1+n2+n3+n4 is equal to

Answer 1

67 relations only because
no. of null set=0
no. of identity relation=0
no. of reflexive relations=2^n²-n=64
no. of universal relation is =3

Answer 2

Answer:

The required value = 67

Step-by-step explanation:

The set is given to be : A = {3, 4, 5}

Number of elements in the set, n = 3

Since, no null element is present in the set

⇒ Number of null relations = 0

Since, no identity element is present in the set

⇒ Number of identity relations = 0

Number of universal relations = n = 3

$\textbf{Number of reflexive relations = }\bf 2^{n^2-n}=2^{9-3}=2^6= 64$

Now, the required value = 0 + 0 + 3 + 64

                                         = 67