Question

Consider the shown arrangement.Assume all surfaces to be smooth.If n represent magnitude of normal reaction between block and wedge ,then acceleration of M along horizontal is equal to

Answer 1

Answer:

According to the problem the magnitude of the the normal reaction is given as n

Now force applied horizontally = m g cos θsinθ

Therefore the  acceleration   will be m g cos θsinθ/M [ where M is the block mass]

Now we know that,

n = mgcosθ

Therefore by substituting the value of n

The acceleration will be  =  nsinθ /M

Answer 2

Explanation:

Nsin/M along -ve x - axis