Chemistry, asked by phantom2709, 7 months ago

Consider the simultaneous equilibrium in a 1L
55.
container:
P(g) = Q(g) +R(g)
Q(g) +S(g) = R(g) +T(g)
P(g) +T(g) = R(g) +S(g)
Initially 1 mole each of P(g) and S(g) are present
5
while at equilibrium, [Q] = [T] and [S]
Mand
6
[R] = 1 M. The value of [S] is found to be x times
[P] at equilibrium. Find (10x).​

Answers

Answered by Anonymous
1

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