Consider the situation of Exercise 2.64. Let A
be the event that the component fails a particular test
and B be the event that the component displays strain
but does not actually fail. Event A occurs with probability
0.20, and event B occurs with probability 0.35.
(a) What is the probability that the component does
not fail the test?
(b) What is the probability that the component works
perfectly well (i.e., neither displays strain nor fails
the test)?
(c) What is the probability that the component either
fails or shows strain in the test?
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Answer:
Step-by-step explanation:
Given,
P(A) = 0.20
P(B) = 0.35
(a) P(A) + P(A’) = 1
P(A’) = 1 - P(A)
= 1 - 0.20
= 0.80
(b) P(B U A)’ = 1 – (0.20 + 0. 35)
= 0.45
(c) P(A U B) = 0.20 + 0.35
= 0.55
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