Question

Consider the situation of the previous problem. If 1⋅0 µC is placed on the upper plate instead of the middle, what will be the potential difference between (a) the upper and the middle plates and (b) the middle and the lower plates?

Answer 1

a) The potential difference between upper and the middle plates is 10V

b) The potential difference between middle and the lower plates is 10V

Explanation:

(a) Given, Charge given to the upper plate P, and Charge is $1 \cdot 0 \mu C$

To find the Charge $Q=+/-(Q 1-Q 2 / 2)$

The potential difference between the plates is given by $\mathrm{v}=\mathrm{Q} / \mathrm{c}$

From the above statement $Q=0.5 \mu C$

Where $C=50 \times 10^{-3}$

Hence $\mathrm{V}=0.5 \times 10^{6} / 50 \times 10^{-3}=10 \mathrm{Volts}$

( b) From the above condition, the upper face of plate Q will get a charge of $-0.5 \mu C$ and this will induce a charge of $+0.5 \mu C$ on the bottom side of plate Q

$\mathrm{v}=\mathrm{Q} / \mathrm{c}$

Hence $\mathrm{v}=+/-0.5 \times 10^{6} / 50 \times 10^{-3}=10 \mathrm{Volts}$