Question

Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Answer 1

Answer:

∴ ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is 81: 1

Explanation:

Given that mirror reflects 64% of intensity of light.

so I1/ I2= 0.64= 16/25

r1/r2= 4/5

so Imax/ I min =( r1+r2)²/(r1-r2)²

=(4+5)²/(4-5)²

= 81:1

∴ ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is 81: 1

Answer 2

Answer:

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