Question

Consider the situation shown in figure (31-E23). The switch S is open for a long time and then closed. (a) Find the charge flown through the battery when the switch S is closed. (b) Find the work done by the battery.
Figure
(c) Find the change in energy stored in the capacitors.
(d) Find the heat developed in the system.

Answer 1

Explanation:

Zero is known as the neutral integer, or the whole number that comes in the middle of the positive and negative numbers on a number line. Zero does not have a positive or negative value. Zero is however considered a whole number, which in turn makes it an integer, but not necessarily a natural number.

Answer 2

a) The charge is flown through the battery (E) = $E \times C/2$

b) Work done = E2C/2

c) Change in energy stored = E2C/4

d) The net charge in the energy is dissipated as heat.

Explanation:

a) Since the switch was open long time, hence the charge flown must be due to both when switch is closed

C = C/2

Hence Q = $E \times C /2$

a) Work done = $q \times v$ = EC/s $\times E$ = E2c/2

b) E = ½ $\times C/2 \times E2$ = E2C/4

c) The net charge in the energy is dissipated as heat.