Consider the situation shown in figure. Mass of the block and the pulley is m. Assume that string and spring are light, find the elongation of the spring at equilibrium.
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The answer is Option a) 2mg/k
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Given:
A system with a light spring, attached to an ideal pulley and a mass m
To Find:
The elongation of the spring at equilibrium
Solution:
At equilibrium position, the net upward force on the mass m will equal the net downward force on it.
The upward force acting on the block is the tension in the string (T) and the downward force is mg.
⇒ T = mg
The spring when pulled downwards produces an equal and opposite restoring force.
Spring Force = k.x
(k = spring constant; x= elongation in the spring)
Since the net downward force = 2 X T
⇒ k.x = 2 XT
or x = 2T/k
Since T=mg,
x = 2mg/k
Hence, the elongation in the spring at equilibrium position is 2mg/k meter.
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