Question

Consider the situation shown in figure. The system is released from rest. The coefficient of friction between block and table is 0.2. The speed of the block of mass 4.0 kg when 2.0 kg mass descend through a distance of 1 m is approximately (g = 10 m/s2) . ​

Answer 1

Answer:

eoq-acrn-bbt ffdhrhrhrhrhrbrhhr

Answer 2

Explanation:

If speed of block of 1.0kg is 0.3

s

m

then speed of 4.0kg block at this instant would be 0.6

s

m

.

and 4 kg block has moved a distance of 2m as 1kg block is moves through 1m distance.

Applying work energy theorem,

E

i

−E

f

= work done against friction

∴0−[

2

1

×1.0×(0.3)

2

+

2

1

×4.0×(0.6)

2

−1×10×1]=μ×4×10×(2)

Solving this equation, we get,

μ=0.12