Question

Consider the straight lines x+2y+4=0x+2y+4=0 
and 4x+2y−1=04x+2y−1=0. The line 6x+6y+7=06x+6y+7=0 is

a) bisector of the angle containing origin

b)bisector of acute angle

c) bisector of obtuse angle

d) bisector of angle not containing origin​

Answer 1

Answer:

$\sqrt{310 \div \sqrt{5} }$