Question

consider the system of equation.x+y+3z=5:x+3y-3z=1, -2x-4y-4z=-10
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Answer 1

x+y+z=6,x+2y+3z=0,x+2y+λz=μ has no solution

⎣

⎢

⎢

⎡

1

1

1

1

2

2

1

3

λ

.

.

.

6

10

μ

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

1

1

0

1

2

0

1

3

3−λ

.

.

.

6

10

10−μ

⎦

⎥

⎥

⎤

Now ∣A∣=0 if λ=3

for λ=3 either infinite solutions exist or no solution exist for no solution μ



=10 if μ=0 infinite solutions exist

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