Question

Consider the system of equations. x2 -3x1 +1.9 = 0 and x2 + x1^2 -3.0 = 0 The next iteration values for x1 and x2 are​​

Answer 1

Answer:

x1 = 1.17

x2 = 1.62

Step-by-step explanation:

Answer 2

Answer:

For  x1 = 1.17 the value of x2 is 1.61

For  x1 = -4.17 the value of x2 is -14.14

Step-by-step explanation:

We are Given 2 equations

$x_2-3x_1+1.9=0 .................(1)\\x_{2} + x_{1} ^2 -3.0 = 0..................(2)$

substituting equation (1) in (2)

we get,

$-x_{1}(3+x_1) = -4.93 \\\\x_1^{2}+3x_1 = 4.93.....................(3)$

on solving equation (3)

we get 2 values of $x_1$

$x_1$= 1.17 and  $x_1$ = -4.17

for the value of $x_2$ , substitute the value of $x_1$ in equation (1)

For x1 = 1.17

$x_2-3(1.17)+1.9=0 \\\\x_2 = 1.61$

For x1 = -4.17

$x_2-3(-4.17)+1.9=0 \\\\x_2 = -14.14$

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