consider the three consecutive numbers a, b and c if there are 54 not perfect square numbers between a and b how many non perfect square numbers lie between the number b and c?
i. 54
ii. 56
iii. 58
iv. 59
Answers
Given : consider the three consecutive numbers a, b and c if there are 54 nom perfect square numbers between a² and b²
(Correction in Question)
To Find : how many non perfect square numbers lie between the number b² and c²
i. 54
ii. 56
iii. 58
iv. 59
Solution:
For two connective positive integers , n and n + 1
Number of non prefect square between n² and ( n + 1)² is given by
2n
a , b and c are three consecutive integers
b = a + 1 , c + 2
N
Number of non prefect square between a² and ( a + 1)²
= 2a = 54
=> a= 27
Number of non prefect square between b² and ( c)²
(a + 1)² and (a + 2)²
= 2 (a + 1)
= 2a + 2
= 54 + 2
= 56
Hence non perfect square numbers lie between the number b² and c² is 56
Correct answer is option ii) 56
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Answer:
2) 56
Step-by-step explanation:
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