Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cycles per instruction (CPI) for A and B are 2.0 and 1.0 respectively for the same program. Which computer is faster and how much?
a) A is 1.33 times faster than B
b) Bis 1.22 times faster than A
c) A is 1.23 times faster than B
d) B is 1.33 times faster than A
Answers
Answered by
12
computer B is Faster
Explanation:
Computer A clock cycle times 100ps
Number of cycle per instruction = 2
Time Required Per instruction = 100 * 2 = 200 ps
Computer B clock cycle times 150ps
Number of cycle per instruction = 1
Time Required Per instruction = 150 * 1 = 150 ps
Computer B requires less time than Computer A per instruction
Computer B is Faster
Computer B is Faster 200 - 150 = 50ps Faster Per instruction
Answered by
13
Answer:
b b is 1.22 times faster than a
Similar questions