Question

Consider the two numbers whose sum is 135 and their HCF is 27. If their LCM is 162, then what will be the larger number?​

Answer 1

Step-by-step explanation:

let the ratio of two no. be x and y

then the no. be 27x and 27y

LCM = product of ratio and hcf

162 = x ×y× 27

162= 27xy

6= xy

sum of no. = 135

27x+27y= 135

27(x+y)=135

(x+y)= 5

on solving eq 1 and 2

we get x=3 and y=2

larger no. be = 27×3 = 81

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