Question

Consider the UDP header 05 31 00 OE 00 1A E3 11. What is the length of the data?
a) 11 bytes
b) 20 bytes
c) 18 bytes
d) 22 bytes​

Answer 1

Explanation:

For any equation in quadratic ,, if it has real and equal roots then the discriminant of the given equation is zero

=> b^2-4ac=0,, for the given equation b= coefficient of 'x' term= -2(k+1),, a= coefficient of 'x^2' = 4 ,, c= constant= k+1

now ,the value of b^2-4ac=(2(k+1))^2-4(4)(k+1)

=>4(k+1)^2-4(k+1)(4)=0 (according to condition )

=>4(k+1)[(k+1)-4]=0 =>k+1-4=0 => k-3= 0

=>k =3

Read more on Brainly.in - https://brainly.in/question/1100066#readmore

Answer 2

Answer:

c) 18 bytes

Explanation:

(001A)16 = 0∙16^3+0∙16^2+1∙16^1+10∙16^0 = 0+0+16+10 = 26 bytes

Happened: 26 bytes

Since, Total length= 26 bytes

and      Data Length=Total length-8 bytes

So,        Data Length=26-8=18