Chemistry, asked by wwaamnakhan1709, 1 month ago

Consider: The ultra violet radiation of frequency 2.73*10^16/s and a yellow light of frequency 5.26*10^14/s. calculate the energy in joules of an individual quantum of each. compare these photons by calculating the ratio of their angles.

Answers

Answered by Abhinav3583
0

Answer:

According to Einstein's photoelectric equation, kinetic energy of photoelectrons, E

k

=hv−W

As E

k

is same, hv

1

−W=hv

2

−W

2

⇒hv

1

−hv

2

=W

1

−W

2

⇒v

1

−v

2

=

h

W

1

−W

2

As W

1

>W

2

,V

1

>V

2

That is, frequency of radiation V

1

is higher.

Answered by madhushathiskar
1

Answer:

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Explanation:

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