Question

Consider the window size is 10, bandwidth is 1500 bps, transmission delay is 2 ms and
propagation delay is 50 ms. What is the throughput using Go Back N protocol?
a) 294.11
b) 140.23
c) 96
d) 154.21​

Answer 1

Given:

Consider the window size is 10, bandwidth is 1500 bps, transmission delay is 2 ms and  propagation delay is 50 ms.

To find:

The throughput using Go Back N protocol

Solution:

n-window size

Throughput is product of bandwidth and efficiency

We know:

Efficiency=$\dfrac{n}{(1+2(\dfrac{PD}{TD} ) )}$

                  =$\dfrac{10}{1+2\times(\dfrac{50}{2} )}$

                   =$10\times\dfrac{1}{51}$

                    =$\dfrac{10}{51}$

Now we get brandwidth:

Bandwidth= 1500

Now we get Throughput:

Throughput = $\dfrac{10}{51}\times 1500$

                     = 0.1960$\times$51

                    =294.117647

Therefore we get option a as the correct answer.