Question

Consider the window size is 10, bandwidth is 1500 bps, transmission delay is 2 and propagation delay is 50 What is the throughput using Go Back N protocol?

Answer 1

Explanation:

Consider the window size is 10, bandwidth is 1500 bps, transmission delay is 2 ms and propagation delay is 50 ms.

To find:

The throughput using Go Back N protocol

Solution:

n-window size

Throughput is product of bandwidth and efficiency

We know:

Efficiency=\dfrac{n}{(1+2(\dfrac{PD}{TD} ) )}

(1+2(

TD

PD

))

n

=\dfrac{10}{1+2\times(\dfrac{50}{2} )}

1+2×(

2

50

)

10

=10\times\dfrac{1}{51}10×

51

1

=\dfrac{10}{51}

51

10

Now we get brandwidth:

Bandwidth= 1500

Now we get Throughput:

Throughput = \dfrac{10}{51}\times 1500

51

10

×1500

= 0.1960\times× 51

=294.117647

Answer 2

=> a = Propagation delay/ Transmission delay

=> a = 50 / 2

=> 25

=> Efficiency = N / (1 + 2a)

=> Efficiency = 10 / (1 + 2 x 25)

=> 10 / (1 + 50)

=> 10 / 51

=> 0.196078

Throughput = Efficiency x Bandwidth

=> 0.196078 x 1500

=> 294.117