Consider this reaction.
mc030-1.jpg
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
1860 mL
2880 mL
3710 mL
45,100 mL
Answers
Answered by
2
2Mg + O₂ --------> 2MgO
2 mole 1 mole 2 mole
48g 22400ml 44800 ml
here it is clear that, 48g Mg reacts with 22400 ml of oxygen at STP
∴ 1 g of Mg reacts with 22400/48 ml of oxygen at STP,
∴ 4.03 g og Mg reacts with 22400/48 × 4.03 ml =1880.66ml of oxygen at STP.
hence, option (a) is nearest value of it. so answer is (a)
2 mole 1 mole 2 mole
48g 22400ml 44800 ml
here it is clear that, 48g Mg reacts with 22400 ml of oxygen at STP
∴ 1 g of Mg reacts with 22400/48 ml of oxygen at STP,
∴ 4.03 g og Mg reacts with 22400/48 × 4.03 ml =1880.66ml of oxygen at STP.
hence, option (a) is nearest value of it. so answer is (a)
Answered by
0
Answer:
A
Explanation:
did it on e2020
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