Question

Consider this reaction.

mc030-1.jpg

What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?

Answer 1

          2Mg     +     O₂ -------->   2MgO   
     2 mole            1 mole             2 mole      
       48g             22400ml        44800 ml
here it is clear that, 48g Mg reacts with 22400 ml of oxygen at STP∴ 1 g of Mg reacts with 22400/48 ml of oxygen at STP,∴ 4.03 g og Mg reacts with 22400/48 × 4.03 ml =1880.66ml  of oxygen at STP.hence, answer is nearest value of 1880.66 ml