Question

consider those numbers between 300 and 400 such that when each number is divided by 6, 9, 12 8 gives 4 as a remainder in each case what is the sum of the number?

Answer 1

We need their common multiple
The common multiple is 312
If we add 4 to it that is 316 then if we divide it by any of these the remainder wil be 4
The sum of digits 3,1,6 is
$3 + 1 + 6 = 10$