consider thr following species N3-,O2-,F-,Na+,Mg2+,Al3+
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OK.considered.now what??
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N3- = 7+3 = 10 e-
O2- = 8+2 = 10 e-
F- = 9+1 = 10 e-
Na+ = 9+1 = 10 e-
Mg2+ = 12-2 = 10 e-
Al3+ = 13-3 = 10 e-
The more + the charge smaller ionic radius .
Al3+ > Mg2+ > Na+ > F- > O2- > N3-
O2- = 8+2 = 10 e-
F- = 9+1 = 10 e-
Na+ = 9+1 = 10 e-
Mg2+ = 12-2 = 10 e-
Al3+ = 13-3 = 10 e-
The more + the charge smaller ionic radius .
Al3+ > Mg2+ > Na+ > F- > O2- > N3-
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