Question

Consider three different raster systems with resolutions of 640 x 480, 1280 x 1024, 2560 x 2048. Find the size of frame buffer (in bytes) is needed for each of these systems to store 12 bits/ pixel.

Answer 1

Solution:-

For 12 bits per pixel:-

Frame buffer size=640* 480*12=3686400/8=460800bytes

Frame buffer size=1280*1024*12=15728640/8=1966080 bytes

Frame buffer size=2560*2048*12=62914560/8=7864320 bytes

For 24 bits per pixel:-

Frame buffer size=640*480*24=7372800/8 =921600bytes

Frame buffer size=1280*1024*24=31457280bits=3932160 bytes

Frame buffer size=2560*2048*24=125829120 bits=15728640 bytes