consider three digit numbers which are multiple of 6 .
i)How many number are there of this type?
Answers
Answered by
0
Answer:
1,2,3 is your answer
1x2x3=6
Step-by-step explanation:
Answered by
0
Answer: 150
Solution: (2 Approachs)
1. It can be solve by using Arithmetic Progression by taking 1st term as 102 and last as 996. And common difference as 6.
Here, last term - first term = 894 and 894/6=149 and 1 term is first term itself, so total terms will be 150.
2. But I will use shortcut for it, I will divide 100 and 1000 both by 6 and take floor value of it.
So, 100/6 = 16(floor) and 1000/6=166,
So, answer is 166-16 = 150.
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