Consider three mixtures - the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1 : 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4 : 3 : 2. Then the resulting mixture has
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There are three mixtures ,the first having water and liquid A in the ratio 1 : 2,
so we can consider only the liquid part which is 2/3.
The second having the water and liquid in the ratio 1 : 3 = 3/4.
The third having the liquid and water in the ratio 1 : 4 = 4/5
⟹ 160x/60 + 135x/60 + 96x/60 = 391x/60
⟹ 540x/60 - 391x/60 = 149x/60 = 2(29/60x)
Where A = 2(2/3x) and B = 2(1/4x)
Hence by this we can infer that more water than liquid B is true
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More water than liquid B
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