Question

Consider triangle OAB with the sides OA and OB given by y = m2, o being origin.
If H (a, b) is the orthocentre, then equation of AB is
(A) (1 -m?) (ax – by) = a + m²b2
(B) (1 + m) (ax + by)=a? - m%b2
(C) (1 - m?) (ax + by) = a? - m%b2
(D) (1 + m²) (ax + by) = a + m%b2​

Answer 1

Answer:

consider of triangle o ab so 1 m =100 mm and a+2 =4and m% ax TX by 120 mm ans