Consider two bodies with masses 2kg and 5kg respectively. Both the bodies are at rest and the same force is acting on both the bodies. What is the ratio of times that is required to reach same final velocity?
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Answer:
Mass of body A, m
A
=5kg
Mass of body B, m
B
=10kg
Applied force, F=200N
Coefficient of friction, μ
s
=0.15
The force of friction is given by the relation:
=0.15(5+10)×10
=1.5×15=22.5N leftward
Net force acting on the partition =200−22.5=177.5N rightward
As per Newtons third law of motion, the reaction force of the partition will be in the direction opposite to the net applied force.
Hence, the reaction of the partition will be 177.5N, in the leftward direction.
Explanation:
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