consider two cars A and B in motion along a straight road .Let us compare the time taken by car A and car B to travel 100m . Car A is moving with a constant speed of 72km /h whereas car B is accelerated uniformly from 36km/h to 108km/h for 50m , on encountering a hurdle it slows down back to 36km/h for next 50m
ANALYSIS
1)Time taken by car A to reach the destination ________
2) Time taken by car B to reach the destination_________
3)Did accelerating to a high speed enable the second driver to complete the journey in less time ????
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Answers
Answered by
2
The relative speed of A wrt B will be V
AB
=V
A
−V
B
=0−1=−1m/s
their relative acceleration will be a
AB
=a
A
−a
B
=4−0=4m/s
2
the distance traveled will be given by s=ut+
2
1
at
2
=(−1)t+
2
1
4×(t)
2
=10meter
or 2t
2
−t−10=0
on solving it we get t=2.5sec
Just employ the Shridharacharya Formula t=
2a
−b±
b
2
−4ac
Where t is root of at
2
+bt+c=
AB
=V
A
−V
B
=0−1=−1m/s
their relative acceleration will be a
AB
=a
A
−a
B
=4−0=4m/s
2
the distance traveled will be given by s=ut+
2
1
at
2
=(−1)t+
2
1
4×(t)
2
=10meter
or 2t
2
−t−10=0
on solving it we get t=2.5sec
Just employ the Shridharacharya Formula t=
2a
−b±
b
2
−4ac
Where t is root of at
2
+bt+c=
Answered by
1
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