Question

consider two forces 4.358 N and 2.452 N acting at right angle to each other on an object at 0 . if Q is third force used to keep the object at equilibrium find the magnitude and direction of Q

Answer 1

two forces 4.358N and 2.452N acting at right angle to each on an object. A third force Q used to keep the object at equilibrium.

Let , A = 4.358N and B = 2.452N

at equilibrium, $F_Q=\sqrt{A^2+B^2}$

so, $F_Q=\sqrt{4.358^2+2.452^2}$

or, $F_Q=\sqrt{18.992164+6.012304}$

hence, F ≈ 5N

so, 5N force is required to keep the object at equilibrium.

and direction of force Q is just opposite of resultant of A and B. as shown in figure.

direction of resultant of A and B = tan^-1(2.452/4.358) with x axis

so, direction of Q tan^-1(2.452/4.358) with negative x axis.