Question

Consider two numbers, whose HCF and LCM are 33 and 264 respectively. The first number is completely divisible by 2 and gives quotient 33. What is the other number?
(a) 66 (b) 132 (c) 58 (d) 73​

Answer 1

Answer:

Let the first number be a and the other number is b.

Therefore, LCM (a,b) = 264 and HCF (a,b) = 33

Since, the first number is completely divided by 2, the quotient is 33, a = 2 × 33 = 66

As we know a × b = LCM(a,b) × HCF(a,b)

Then b = [LCM(a,b) × HCF(a,b)] ÷ a

b = (264 × 33) ÷ 66 = 132

Thus, if the HCF and LCM of two numbers are 33 and 264 respectively, and when the first number is completely divided by 2 for which the quotient is 33, the other number is 132.

Explanation:

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Answer 2

Answer:

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